Base | Representation |
---|---|
bin | 1010001100010100000110… |
… | …11011111111000100011111 |
3 | 2221100200202111220200001012 |
4 | 11012022003123333010133 |
5 | 10414210012143031142 |
6 | 115400314234205435 |
7 | 4502211366563522 |
oct | 506120333770437 |
9 | 87320674820035 |
10 | 22413344502047 |
11 | 716149a725104 |
12 | 261ba3388387b |
13 | c67752a379a5 |
14 | 576b512b4bb9 |
15 | 28d05105d882 |
hex | 1462836ff11f |
22413344502047 has 2 divisors, whose sum is σ = 22413344502048. Its totient is φ = 22413344502046.
The previous prime is 22413344501881. The next prime is 22413344502049. The reversal of 22413344502047 is 74020544331422.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 22413344502047 - 214 = 22413344485663 is a prime.
Together with 22413344502049, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 22413344501995 and 22413344502013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (22413344502049) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11206672251023 + 11206672251024.
It is an arithmetic number, because the mean of its divisors is an integer number (11206672251024).
Almost surely, 222413344502047 is an apocalyptic number.
22413344502047 is a deficient number, since it is larger than the sum of its proper divisors (1).
22413344502047 is an equidigital number, since it uses as much as digits as its factorization.
22413344502047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 645120, while the sum is 41.
Adding to 22413344502047 its reverse (74020544331422), we get a palindrome (96433888833469).
The spelling of 22413344502047 in words is "twenty-two trillion, four hundred thirteen billion, three hundred forty-four million, five hundred two thousand, forty-seven".
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