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22430042021477 is a prime number
BaseRepresentation
bin1010001100110011001101…
…01011111101111001100101
32221102021212012020112121202
411012121212223331321211
510414443211224141402
6115412115152052245
74503342231264266
oct506314653757145
987367765215552
1022430042021477
117168588a75642
122623113834085
13c691b41721bc
14577896b3696d
1528d6cbdd6b02
hex146666afde65

22430042021477 has 2 divisors, whose sum is σ = 22430042021478. Its totient is φ = 22430042021476.

The previous prime is 22430042021423. The next prime is 22430042021483. The reversal of 22430042021477 is 77412024003422.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19431045860356 + 2998996161121 = 4408066^2 + 1731761^2 .

It is a cyclic number.

It is not a de Polignac number, because 22430042021477 - 210 = 22430042020453 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 22430042021477.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (22430042021407) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11215021010738 + 11215021010739.

It is an arithmetic number, because the mean of its divisors is an integer number (11215021010739).

Almost surely, 222430042021477 is an apocalyptic number.

It is an amenable number.

22430042021477 is a deficient number, since it is larger than the sum of its proper divisors (1).

22430042021477 is an equidigital number, since it uses as much as digits as its factorization.

22430042021477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 150528, while the sum is 38.

Adding to 22430042021477 its reverse (77412024003422), we get a palindrome (99842066024899).

The spelling of 22430042021477 in words is "twenty-two trillion, four hundred thirty billion, forty-two million, twenty-one thousand, four hundred seventy-seven".