Base | Representation |
---|---|
bin | 110011001011101100111001… |
… | …110101010011001010101111 |
3 | 1002112000210001201200220120011 |
4 | 303023230321311103022233 |
5 | 214001103004303132421 |
6 | 2114431325200034051 |
7 | 65262156250006465 |
oct | 6313547165231257 |
9 | 1075023051626504 |
10 | 225104501224111 |
11 | 657a831252a273 |
12 | 212b6916002927 |
13 | 987b35685b312 |
14 | 3d8318a3d2835 |
15 | 1b05740b124e1 |
hex | ccbb39d532af |
225104501224111 has 2 divisors, whose sum is σ = 225104501224112. Its totient is φ = 225104501224110.
The previous prime is 225104501224087. The next prime is 225104501224139. The reversal of 225104501224111 is 111422105401522.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 225104501224111 - 223 = 225104492835503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (225104501221111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 112552250612055 + 112552250612056.
It is an arithmetic number, because the mean of its divisors is an integer number (112552250612056).
Almost surely, 2225104501224111 is an apocalyptic number.
225104501224111 is a deficient number, since it is larger than the sum of its proper divisors (1).
225104501224111 is an equidigital number, since it uses as much as digits as its factorization.
225104501224111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6400, while the sum is 31.
Adding to 225104501224111 its reverse (111422105401522), we get a palindrome (336526606625633).
The spelling of 225104501224111 in words is "two hundred twenty-five trillion, one hundred four billion, five hundred one million, two hundred twenty-four thousand, one hundred eleven".
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