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23002333300213 is a prime number
BaseRepresentation
bin1010011101011101001011…
…11001111100010111110101
310000110000001011020201021021
411032232211321330113311
511003332234311101323
6120531043120221141
74562602156012351
oct516564571742765
9100400034221237
1023002333300213
1173692645297a3
1226b600aa6a7b1
13cab159347c47
14597466db0461
1529d52437805d
hex14eba5e7c5f5

23002333300213 has 2 divisors, whose sum is σ = 23002333300214. Its totient is φ = 23002333300212.

The previous prime is 23002333300207. The next prime is 23002333300229. The reversal of 23002333300213 is 31200333320032.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 15683485016644 + 7318848283569 = 3960238^2 + 2705337^2 .

It is a cyclic number.

It is not a de Polignac number, because 23002333300213 - 229 = 23001796429301 is a prime.

It is a super-4 number, since 4×230023333002134 (a number of 55 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23002333300813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11501166650106 + 11501166650107.

It is an arithmetic number, because the mean of its divisors is an integer number (11501166650107).

Almost surely, 223002333300213 is an apocalyptic number.

It is an amenable number.

23002333300213 is a deficient number, since it is larger than the sum of its proper divisors (1).

23002333300213 is an equidigital number, since it uses as much as digits as its factorization.

23002333300213 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5832, while the sum is 25.

Adding to 23002333300213 its reverse (31200333320032), we get a palindrome (54202666620245).

The spelling of 23002333300213 in words is "twenty-three trillion, two billion, three hundred thirty-three million, three hundred thousand, two hundred thirteen".