Base | Representation |
---|---|
bin | 1010011110010011001110… |
… | …00001101101000110100011 |
3 | 10000112202220220101022221102 |
4 | 11033021213001231012203 |
5 | 11004321142321010113 |
6 | 120552241501545015 |
7 | 4564650103415441 |
oct | 517114701550643 |
9 | 100482826338842 |
10 | 23031343141283 |
11 | 737a5a0860764 |
12 | 26bb76627516b |
13 | cb0b0053a289 |
14 | 598a19b0db91 |
15 | 29e1710b6758 |
hex | 14f26706d1a3 |
23031343141283 has 2 divisors, whose sum is σ = 23031343141284. Its totient is φ = 23031343141282.
The previous prime is 23031343141201. The next prime is 23031343141321. The reversal of 23031343141283 is 38214134313032.
It is an a-pointer prime, because the next prime (23031343141321) can be obtained adding 23031343141283 to its sum of digits (38).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23031343141283 - 214 = 23031343124899 is a prime.
It is not a weakly prime, because it can be changed into another prime (23031343141483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11515671570641 + 11515671570642.
It is an arithmetic number, because the mean of its divisors is an integer number (11515671570642).
Almost surely, 223031343141283 is an apocalyptic number.
23031343141283 is a deficient number, since it is larger than the sum of its proper divisors (1).
23031343141283 is an equidigital number, since it uses as much as digits as its factorization.
23031343141283 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 124416, while the sum is 38.
The spelling of 23031343141283 in words is "twenty-three trillion, thirty-one billion, three hundred forty-three million, one hundred forty-one thousand, two hundred eighty-three".
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