Base | Representation |
---|---|
bin | 1010011110011000001100… |
… | …01111111001111101011101 |
3 | 10000120000211001220102200102 |
4 | 11033030012033321331131 |
5 | 11004342130144110214 |
6 | 120553402525110445 |
7 | 4565103231166244 |
oct | 517140617717535 |
9 | 100500731812612 |
10 | 23034014441309 |
11 | 7380741724a33 |
12 | 27001909b8425 |
13 | cb1137ab5691 |
14 | 598bd07d195b |
15 | 29e27a87cbde |
hex | 14f3063f9f5d |
23034014441309 has 2 divisors, whose sum is σ = 23034014441310. Its totient is φ = 23034014441308.
The previous prime is 23034014441299. The next prime is 23034014441423. The reversal of 23034014441309 is 90314441043032.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12394694772100 + 10639319669209 = 3520610^2 + 3261797^2 .
It is a cyclic number.
It is not a de Polignac number, because 23034014441309 - 216 = 23034014375773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23034014446309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11517007220654 + 11517007220655.
It is an arithmetic number, because the mean of its divisors is an integer number (11517007220655).
Almost surely, 223034014441309 is an apocalyptic number.
It is an amenable number.
23034014441309 is a deficient number, since it is larger than the sum of its proper divisors (1).
23034014441309 is an equidigital number, since it uses as much as digits as its factorization.
23034014441309 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 38.
The spelling of 23034014441309 in words is "twenty-three trillion, thirty-four billion, fourteen million, four hundred forty-one thousand, three hundred nine".
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