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230410472127151 is a prime number
BaseRepresentation
bin110100011000111010011110…
…010101111111101010101111
31010012211000200222001100212111
4310120322132111333222233
5220200021121331032101
62134013035402544451
766350415202355011
oct6430723625775257
91105730628040774
10230410472127151
11674635947aa938
1221a13114b08127
139b747ca79ccb4
1440c7cd7cb41b1
151b98789cce251
hexd18e9e57faaf

230410472127151 has 2 divisors, whose sum is σ = 230410472127152. Its totient is φ = 230410472127150.

The previous prime is 230410472127127. The next prime is 230410472127191. The reversal of 230410472127151 is 151721274014032.

It is an a-pointer prime, because the next prime (230410472127191) can be obtained adding 230410472127151 to its sum of digits (40).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 230410472127151 - 217 = 230410471996079 is a prime.

It is a super-2 number, since 2×2304104721271512 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (230410472127191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115205236063575 + 115205236063576.

It is an arithmetic number, because the mean of its divisors is an integer number (115205236063576).

Almost surely, 2230410472127151 is an apocalyptic number.

230410472127151 is a deficient number, since it is larger than the sum of its proper divisors (1).

230410472127151 is an equidigital number, since it uses as much as digits as its factorization.

230410472127151 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 94080, while the sum is 40.

The spelling of 230410472127151 in words is "two hundred thirty trillion, four hundred ten billion, four hundred seventy-two million, one hundred twenty-seven thousand, one hundred fifty-one".