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2304122412013 is a prime number
BaseRepresentation
bin100001100001111000011…
…001011101101111101101
322011021100020211002212121
4201201320121131233231
5300222320314141023
64522255455432541
7325316205232342
oct41417031355755
98137306732777
102304122412013
1180919a040264
12312679b25751
1313937c474416
147d73d2cc7c9
153ee07541d5d
hex2187865dbed

2304122412013 has 2 divisors, whose sum is σ = 2304122412014. Its totient is φ = 2304122412012.

The previous prime is 2304122411993. The next prime is 2304122412071. The reversal of 2304122412013 is 3102142214032.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2220567884649 + 83554527364 = 1490157^2 + 289058^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2304122412013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2304122412083) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1152061206006 + 1152061206007.

It is an arithmetic number, because the mean of its divisors is an integer number (1152061206007).

Almost surely, 22304122412013 is an apocalyptic number.

It is an amenable number.

2304122412013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2304122412013 is an equidigital number, since it uses as much as digits as its factorization.

2304122412013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 2304122412013 its reverse (3102142214032), we get a palindrome (5406264626045).

The spelling of 2304122412013 in words is "two trillion, three hundred four billion, one hundred twenty-two million, four hundred twelve thousand, thirteen".