23041401221 has 2 divisors, whose sum is σ = 23041401222. Its totient is φ = 23041401220.

The previous prime is 23041401133. The next prime is 23041401223. The reversal of 23041401221 is 12210414032.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17242578721 + 5798822500 = 131311^2 + 76150^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-23041401221 is a prime.

Together with 23041401223, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23041401193 and 23041401202.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23041401223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11520700610 + 11520700611.

It is an arithmetic number, because the mean of its divisors is an integer number (11520700611).

Almost surely, 2^23041401221 is an apocalyptic number.

It is an amenable number.

23041401221 is a deficient number, since it is larger than the sum of its proper divisors (1).

23041401221 is an equidigital number, since it uses as much as digits as its factorization.

23041401221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 23041401221 its reverse (12210414032), we get a palindrome (35251815253).

The spelling of 23041401221 in words is "twenty-three billion, forty-one million, four hundred one thousand, two hundred twenty-one".