Search a number
-
+
23044101339197 is a prime number
BaseRepresentation
bin1010011110101010111110…
…11110010111100000111101
310000120222212001011221022002
411033111133132113200331
511010023304420323242
6121002151454232045
74565611212333641
oct517253736274075
9100528761157262
1023044101339197
117384a484a1684
122702126ab5625
13cb20847a9b03
145994aa2d4c21
1529e66b1a3432
hex14f55f79783d

23044101339197 has 2 divisors, whose sum is σ = 23044101339198. Its totient is φ = 23044101339196.

The previous prime is 23044101339163. The next prime is 23044101339293. The reversal of 23044101339197 is 79193310144032.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 17054868100516 + 5989233238681 = 4129754^2 + 2447291^2 .

It is a cyclic number.

It is not a de Polignac number, because 23044101339197 - 234 = 23026921470013 is a prime.

It is a super-3 number, since 3×230441013391973 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23044101336197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11522050669598 + 11522050669599.

It is an arithmetic number, because the mean of its divisors is an integer number (11522050669599).

Almost surely, 223044101339197 is an apocalyptic number.

It is an amenable number.

23044101339197 is a deficient number, since it is larger than the sum of its proper divisors (1).

23044101339197 is an equidigital number, since it uses as much as digits as its factorization.

23044101339197 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 489888, while the sum is 47.

The spelling of 23044101339197 in words is "twenty-three trillion, forty-four billion, one hundred one million, three hundred thirty-nine thousand, one hundred ninety-seven".