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23101303314317 is a prime number
BaseRepresentation
bin1010100000010101100001…
…11110100101011110001101
310000210110111112210100111012
411100022300332211132031
511011442432122024232
6121044331531135005
74603004555160464
oct520126076453615
9100713445710435
1023101303314317
1173a7231520188
12271122b8a4465
13cb759c64ba77
1459c1753199db
152a0db7e5b9b2
hex1502b0fa578d

23101303314317 has 2 divisors, whose sum is σ = 23101303314318. Its totient is φ = 23101303314316.

The previous prime is 23101303314293. The next prime is 23101303314359. The reversal of 23101303314317 is 71341330310132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 16505929437001 + 6595373877316 = 4062749^2 + 2568146^2 .

It is a cyclic number.

It is not a de Polignac number, because 23101303314317 - 26 = 23101303314253 is a prime.

It is a super-3 number, since 3×231013033143173 (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23101303314917) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11550651657158 + 11550651657159.

It is an arithmetic number, because the mean of its divisors is an integer number (11550651657159).

Almost surely, 223101303314317 is an apocalyptic number.

It is an amenable number.

23101303314317 is a deficient number, since it is larger than the sum of its proper divisors (1).

23101303314317 is an equidigital number, since it uses as much as digits as its factorization.

23101303314317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13608, while the sum is 32.

Adding to 23101303314317 its reverse (71341330310132), we get a palindrome (94442633624449).

The spelling of 23101303314317 in words is "twenty-three trillion, one hundred one billion, three hundred three million, three hundred fourteen thousand, three hundred seventeen".