Base | Representation |
---|---|
bin | 1010100000010110110110… |
… | …01010001111010000100101 |
3 | 10000210112022212110010101102 |
4 | 11100023123022033100211 |
5 | 11012000404304342013 |
6 | 121044530051405445 |
7 | 4603031240412434 |
oct | 520133312172045 |
9 | 100715285403342 |
10 | 23102011012133 |
11 | 73a7564a48009 |
12 | 27113a88b3885 |
13 | cb7683154b81 |
14 | 59c2012d911b |
15 | 2a0e0a14ed58 |
hex | 1502db28f425 |
23102011012133 has 2 divisors, whose sum is σ = 23102011012134. Its totient is φ = 23102011012132.
The previous prime is 23102011012127. The next prime is 23102011012141. The reversal of 23102011012133 is 33121011020132.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15714231517924 + 7387779494209 = 3964118^2 + 2718047^2 .
It is a cyclic number.
It is not a de Polignac number, because 23102011012133 - 210 = 23102011011109 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23102011012153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11551005506066 + 11551005506067.
It is an arithmetic number, because the mean of its divisors is an integer number (11551005506067).
Almost surely, 223102011012133 is an apocalyptic number.
It is an amenable number.
23102011012133 is a deficient number, since it is larger than the sum of its proper divisors (1).
23102011012133 is an equidigital number, since it uses as much as digits as its factorization.
23102011012133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 23102011012133 its reverse (33121011020132), we get a palindrome (56223022032265).
The spelling of 23102011012133 in words is "twenty-three trillion, one hundred two billion, eleven million, twelve thousand, one hundred thirty-three".
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