Base | Representation |
---|---|
bin | 1010100000100001110111… |
… | …01111000011110111000111 |
3 | 10000211002121010000002011001 |
4 | 11100100323233003313013 |
5 | 11012100013104313212 |
6 | 121051345035354131 |
7 | 4603330645150645 |
oct | 520207357036707 |
9 | 100732533002131 |
10 | 23107926244807 |
11 | 73aa01aa40958 |
12 | 27125798b2947 |
13 | cb80b67b1651 |
14 | 59c602b60195 |
15 | 2a11545e1657 |
hex | 15043bbc3dc7 |
23107926244807 has 2 divisors, whose sum is σ = 23107926244808. Its totient is φ = 23107926244806.
The previous prime is 23107926244801. The next prime is 23107926244813. The reversal of 23107926244807 is 70844262970132.
It is a balanced prime because it is at equal distance from previous prime (23107926244801) and next prime (23107926244813).
It is a cyclic number.
It is not a de Polignac number, because 23107926244807 - 211 = 23107926242759 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23107926244801) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11553963122403 + 11553963122404.
It is an arithmetic number, because the mean of its divisors is an integer number (11553963122404).
Almost surely, 223107926244807 is an apocalyptic number.
23107926244807 is a deficient number, since it is larger than the sum of its proper divisors (1).
23107926244807 is an equidigital number, since it uses as much as digits as its factorization.
23107926244807 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8128512, while the sum is 55.
The spelling of 23107926244807 in words is "twenty-three trillion, one hundred seven billion, nine hundred twenty-six million, two hundred forty-four thousand, eight hundred seven".
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