Base | Representation |
---|---|
bin | 1010100000100111111110… |
… | …01000011001000000001111 |
3 | 10000211102001120111202110121 |
4 | 11100103333020121000033 |
5 | 11012123221314122002 |
6 | 121053050222445411 |
7 | 4603505122315354 |
oct | 520237710310017 |
9 | 100742046452417 |
10 | 23111204442127 |
11 | 740045244403a |
12 | 2713133733867 |
13 | cb84b99cbb89 |
14 | 59c8342a262b |
15 | 2a12972d9237 |
hex | 1504ff21900f |
23111204442127 has 2 divisors, whose sum is σ = 23111204442128. Its totient is φ = 23111204442126.
The previous prime is 23111204442107. The next prime is 23111204442149. The reversal of 23111204442127 is 72124440211132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23111204442127 - 219 = 23111203917839 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 23111204442092 and 23111204442101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23111204442107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11555602221063 + 11555602221064.
It is an arithmetic number, because the mean of its divisors is an integer number (11555602221064).
Almost surely, 223111204442127 is an apocalyptic number.
23111204442127 is a deficient number, since it is larger than the sum of its proper divisors (1).
23111204442127 is an equidigital number, since it uses as much as digits as its factorization.
23111204442127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21504, while the sum is 34.
Adding to 23111204442127 its reverse (72124440211132), we get a palindrome (95235644653259).
The spelling of 23111204442127 in words is "twenty-three trillion, one hundred eleven billion, two hundred four million, four hundred forty-two thousand, one hundred twenty-seven".
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