Base | Representation |
---|---|
bin | 1010100000100111111111… |
… | …01100110110110010010100 |
3 | 10000211102002020111102012001 |
4 | 11100103333230312302110 |
5 | 11012123231241020200 |
6 | 121053051203405044 |
7 | 4603505266500565 |
oct | 520237754666224 |
9 | 100742066442161 |
10 | 23111214001300 |
11 | 7400457882a87 |
12 | 2713136983784 |
13 | cb84bb997ba9 |
14 | 59c83567016c |
15 | 2a129807676a |
hex | 1504ffb36c94 |
23111214001300 has 72 divisors (see below), whose sum is σ = 51895697073920. Its totient is φ = 8924402361600.
The previous prime is 23111214001283. The next prime is 23111214001327. The reversal of 23111214001300 is 310041211132.
It is a super-2 number, since 2×231112140013002 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 7846074 + ... + 10381873.
Almost surely, 223111214001300 is an apocalyptic number.
23111214001300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
23111214001300 is an abundant number, since it is smaller than the sum of its proper divisors (28784483072620).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
23111214001300 is a wasteful number, since it uses less digits than its factorization.
23111214001300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18228401 (or 18228394 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 23111214001300 its reverse (310041211132), we get a palindrome (23421255212432).
The spelling of 23111214001300 in words is "twenty-three trillion, one hundred eleven billion, two hundred fourteen million, one thousand, three hundred".
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