Base | Representation |
---|---|
bin | 100001101000011010000… |
… | …111010110111110101101 |
3 | 22011221102122211222220101 |
4 | 201220122013112332231 |
5 | 300331143404320442 |
6 | 4525415124151101 |
7 | 325654653322234 |
oct | 41503207267655 |
9 | 8157378758811 |
10 | 2311130541997 |
11 | 811165a38022 |
12 | 313ab4b38491 |
13 | 139c283659b4 |
14 | 7dc05d63b1b |
15 | 401b7914cb7 |
hex | 21a1a1d6fad |
2311130541997 has 2 divisors, whose sum is σ = 2311130541998. Its totient is φ = 2311130541996.
The previous prime is 2311130541991. The next prime is 2311130542003. The reversal of 2311130541997 is 7991450311132.
It is a balanced prime because it is at equal distance from previous prime (2311130541991) and next prime (2311130542003).
It can be written as a sum of positive squares in only one way, i.e., 1496135063556 + 814995478441 = 1223166^2 + 902771^2 .
It is a cyclic number.
It is not a de Polignac number, because 2311130541997 - 219 = 2311130017709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2311130541991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1155565270998 + 1155565270999.
It is an arithmetic number, because the mean of its divisors is an integer number (1155565270999).
Almost surely, 22311130541997 is an apocalyptic number.
It is an amenable number.
2311130541997 is a deficient number, since it is larger than the sum of its proper divisors (1).
2311130541997 is an equidigital number, since it uses as much as digits as its factorization.
2311130541997 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 204120, while the sum is 46.
The spelling of 2311130541997 in words is "two trillion, three hundred eleven billion, one hundred thirty million, five hundred forty-one thousand, nine hundred ninety-seven".
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