Base | Representation |
---|---|
bin | 1010100000101001101010… |
… | …01111101000111011001101 |
3 | 10000211111101211211022211012 |
4 | 11100110311033220323031 |
5 | 11012132101222441023 |
6 | 121053320253335005 |
7 | 4603536455142344 |
oct | 520246517507315 |
9 | 100744354738735 |
10 | 23112112312013 |
11 | 740087896112a |
12 | 2713347797465 |
13 | cb8602b1c6aa |
14 | 59c8bcaaab5b |
15 | 2a12ebd6c978 |
hex | 1505353e8ecd |
23112112312013 has 2 divisors, whose sum is σ = 23112112312014. Its totient is φ = 23112112312012.
The previous prime is 23112112311971. The next prime is 23112112312057. The reversal of 23112112312013 is 31021321121132.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22218750860329 + 893361451684 = 4713677^2 + 945178^2 .
It is a cyclic number.
It is not a de Polignac number, because 23112112312013 - 228 = 23111843876557 is a prime.
It is a super-2 number, since 2×231121123120132 (a number of 28 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 23112112312013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23112112318013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556056156006 + 11556056156007.
It is an arithmetic number, because the mean of its divisors is an integer number (11556056156007).
Almost surely, 223112112312013 is an apocalyptic number.
It is an amenable number.
23112112312013 is a deficient number, since it is larger than the sum of its proper divisors (1).
23112112312013 is an equidigital number, since it uses as much as digits as its factorization.
23112112312013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 23112112312013 its reverse (31021321121132), we get a palindrome (54133433433145).
The spelling of 23112112312013 in words is "twenty-three trillion, one hundred twelve billion, one hundred twelve million, three hundred twelve thousand, thirteen".
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