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23112211213151 is a prime number
BaseRepresentation
bin1010100000101001110110…
…01000111010101101011111
310000211111122201221000200022
411100110323020322231133
511012132302032310101
6121053334145222355
74603542065610014
oct520247310725537
9100744581830608
1023112211213151
117400919772005
1227133749319bb
13cb861a469c88
1459c8cbc9370b
152a13058a6a1b
hex15053b23ab5f

23112211213151 has 2 divisors, whose sum is σ = 23112211213152. Its totient is φ = 23112211213150.

The previous prime is 23112211213093. The next prime is 23112211213153. The reversal of 23112211213151 is 15131211221132.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23112211213151 is a prime.

It is a super-2 number, since 2×231122112131512 (a number of 28 digits) contains 22 as substring.

Together with 23112211213153, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23112211213151.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23112211213153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556105606575 + 11556105606576.

It is an arithmetic number, because the mean of its divisors is an integer number (11556105606576).

Almost surely, 223112211213151 is an apocalyptic number.

23112211213151 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112211213151 is an equidigital number, since it uses as much as digits as its factorization.

23112211213151 is an evil number, because the sum of its binary digits is even.

The product of its digits is 720, while the sum is 26.

Adding to 23112211213151 its reverse (15131211221132), we get a palindrome (38243422434283).

The spelling of 23112211213151 in words is "twenty-three trillion, one hundred twelve billion, two hundred eleven million, two hundred thirteen thousand, one hundred fifty-one".