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23112564429701 is a prime number
BaseRepresentation
bin1010100000101010100000…
…01100010101001110000101
310000211112120100120021200202
411100111100030111032011
511012134012443222301
6121053433204020245
74603553615111615
oct520252014251605
9100745510507622
1023112564429701
117400a9009390a
122713453091685
13cb86756ab256
1459c922b5aa45
152a13268c866b
hex150550315385

23112564429701 has 2 divisors, whose sum is σ = 23112564429702. Its totient is φ = 23112564429700.

The previous prime is 23112564429659. The next prime is 23112564429709. The reversal of 23112564429701 is 10792446521132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22908236925025 + 204327504676 = 4786255^2 + 452026^2 .

It is a cyclic number.

It is not a de Polignac number, because 23112564429701 - 230 = 23111490687877 is a prime.

It is a super-2 number, since 2×231125644297012 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23112564429709) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556282214850 + 11556282214851.

It is an arithmetic number, because the mean of its divisors is an integer number (11556282214851).

Almost surely, 223112564429701 is an apocalyptic number.

It is an amenable number.

23112564429701 is a deficient number, since it is larger than the sum of its proper divisors (1).

23112564429701 is an equidigital number, since it uses as much as digits as its factorization.

23112564429701 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 725760, while the sum is 47.

The spelling of 23112564429701 in words is "twenty-three trillion, one hundred twelve billion, five hundred sixty-four million, four hundred twenty-nine thousand, seven hundred one".