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23113011133 is a prime number
BaseRepresentation
bin10101100001101001…
…001000111110111101
32012122210012121201101
4111201221020332331
5334313412324013
614341252013101
71445522232052
oct254151107675
965583177641
1023113011133
1198907683a3
124590601191
132244609c64
141193909029
159041d48dd
hex561a48fbd

23113011133 has 2 divisors, whose sum is σ = 23113011134. Its totient is φ = 23113011132.

The previous prime is 23113011091. The next prime is 23113011191. The reversal of 23113011133 is 33111031132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 22536915129 + 576096004 = 150123^2 + 24002^2 .

It is a cyclic number.

It is not a de Polignac number, because 23113011133 - 217 = 23112880061 is a prime.

It is a super-2 number, since 2×231130111332 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 23113011133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23113011193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11556505566 + 11556505567.

It is an arithmetic number, because the mean of its divisors is an integer number (11556505567).

Almost surely, 223113011133 is an apocalyptic number.

It is an amenable number.

23113011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

23113011133 is an equidigital number, since it uses as much as digits as its factorization.

23113011133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 23113011133 its reverse (33111031132), we get a palindrome (56224042265).

The spelling of 23113011133 in words is "twenty-three billion, one hundred thirteen million, eleven thousand, one hundred thirty-three".