Base | Representation |
---|---|
bin | 1010100000101101001011… |
… | …11100100100010010001111 |
3 | 10000211200021121202020000102 |
4 | 11100112211330210102033 |
5 | 11012144434300401204 |
6 | 121054232040321315 |
7 | 4603634354661536 |
oct | 520264574442217 |
9 | 100750247666012 |
10 | 23114003137679 |
11 | 7401659210473 |
12 | 2713794a7323b |
13 | cb884479044c |
14 | 59ca1bc6731d |
15 | 2a13acd6741e |
hex | 1505a5f2448f |
23114003137679 has 2 divisors, whose sum is σ = 23114003137680. Its totient is φ = 23114003137678.
The previous prime is 23114003137661. The next prime is 23114003137717. The reversal of 23114003137679 is 97673130041132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23114003137679 - 212 = 23114003133583 is a prime.
It is a super-3 number, since 3×231140031376793 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23114003137079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557001568839 + 11557001568840.
It is an arithmetic number, because the mean of its divisors is an integer number (11557001568840).
Almost surely, 223114003137679 is an apocalyptic number.
23114003137679 is a deficient number, since it is larger than the sum of its proper divisors (1).
23114003137679 is an equidigital number, since it uses as much as digits as its factorization.
23114003137679 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 571536, while the sum is 47.
The spelling of 23114003137679 in words is "twenty-three trillion, one hundred fourteen billion, three million, one hundred thirty-seven thousand, six hundred seventy-nine".
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