Base | Representation |
---|---|
bin | 1010100000101101001011… |
… | …11100110100010001010101 |
3 | 10000211200021121212112211112 |
4 | 11100112211330310101111 |
5 | 11012144434310000112 |
6 | 121054232041544405 |
7 | 4603634355353456 |
oct | 520264574642125 |
9 | 100750247775745 |
10 | 23114003203157 |
11 | 7401659255689 |
12 | 2713794aa5105 |
13 | cb88447b41a9 |
14 | 59ca1bc8312d |
15 | 2a13acd7ba22 |
hex | 1505a5f34455 |
23114003203157 has 2 divisors, whose sum is σ = 23114003203158. Its totient is φ = 23114003203156.
The previous prime is 23114003203147. The next prime is 23114003203217. The reversal of 23114003203157 is 75130230041132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12442896447601 + 10671106755556 = 3527449^2 + 3266666^2 .
It is a cyclic number.
It is not a de Polignac number, because 23114003203157 - 214 = 23114003186773 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23114003203147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557001601578 + 11557001601579.
It is an arithmetic number, because the mean of its divisors is an integer number (11557001601579).
Almost surely, 223114003203157 is an apocalyptic number.
It is an amenable number.
23114003203157 is a deficient number, since it is larger than the sum of its proper divisors (1).
23114003203157 is an equidigital number, since it uses as much as digits as its factorization.
23114003203157 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 32.
Adding to 23114003203157 its reverse (75130230041132), we get a palindrome (98244233244289).
The spelling of 23114003203157 in words is "twenty-three trillion, one hundred fourteen billion, three million, two hundred three thousand, one hundred fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •