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231140234314399 is a prime number
BaseRepresentation
bin110100100011100010000111…
…100011110100001010011111
31010022101210100100100112012211
4310203202013203310022133
5220244000144441030044
62135332205135141251
766454221323534524
oct6443420743641237
91108353310315184
10231140234314399
11677150285032a3
1221b10638974827
139bc8579c68907
144111365bdb14b
151bac74bb87634
hexd238878f429f

231140234314399 has 2 divisors, whose sum is σ = 231140234314400. Its totient is φ = 231140234314398.

The previous prime is 231140234314387. The next prime is 231140234314411. The reversal of 231140234314399 is 993413432041132.

231140234314399 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a balanced prime because it is at equal distance from previous prime (231140234314387) and next prime (231140234314411).

It is a cyclic number.

It is not a de Polignac number, because 231140234314399 - 225 = 231140200759967 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231140234314369) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115570117157199 + 115570117157200.

It is an arithmetic number, because the mean of its divisors is an integer number (115570117157200).

Almost surely, 2231140234314399 is an apocalyptic number.

231140234314399 is a deficient number, since it is larger than the sum of its proper divisors (1).

231140234314399 is an equidigital number, since it uses as much as digits as its factorization.

231140234314399 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1679616, while the sum is 49.

The spelling of 231140234314399 in words is "two hundred thirty-one trillion, one hundred forty billion, two hundred thirty-four million, three hundred fourteen thousand, three hundred ninety-nine".