Base | Representation |
---|---|
bin | 1010100000101111011111… |
… | …10110110101111100010111 |
3 | 10000211210111001001102200102 |
4 | 11100113233312311330113 |
5 | 11012210004221314002 |
6 | 121054555054204315 |
7 | 4604010162632231 |
oct | 520275766657427 |
9 | 100753431042612 |
10 | 23115243151127 |
11 | 7402135166976 |
12 | 2713a801b369b |
13 | cb89b165460a |
14 | 59cad8811251 |
15 | 2a1431b58a02 |
hex | 1505efdb5f17 |
23115243151127 has 2 divisors, whose sum is σ = 23115243151128. Its totient is φ = 23115243151126.
The previous prime is 23115243151081. The next prime is 23115243151201. The reversal of 23115243151127 is 72115134251132.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23115243151127 is a prime.
It is a super-2 number, since 2×231152431511272 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23115243154127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11557621575563 + 11557621575564.
It is an arithmetic number, because the mean of its divisors is an integer number (11557621575564).
Almost surely, 223115243151127 is an apocalyptic number.
23115243151127 is a deficient number, since it is larger than the sum of its proper divisors (1).
23115243151127 is an equidigital number, since it uses as much as digits as its factorization.
23115243151127 is an evil number, because the sum of its binary digits is even.
The product of its digits is 50400, while the sum is 38.
The spelling of 23115243151127 in words is "twenty-three trillion, one hundred fifteen billion, two hundred forty-three million, one hundred fifty-one thousand, one hundred twenty-seven".
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