Base | Representation |
---|---|
bin | 1010100000111000110000… |
… | …01001100110011011011101 |
3 | 10000212021022110211000212012 |
4 | 11100130120021212123131 |
5 | 11012300144303434003 |
6 | 121101140231321005 |
7 | 4604244313333241 |
oct | 520343011463335 |
9 | 100767273730765 |
10 | 23120214124253 |
11 | 7404256148624 |
12 | 2714a28b20165 |
13 | cb92c448c12c |
14 | 59d04aab8421 |
15 | 2a16232798d8 |
hex | 1507182666dd |
23120214124253 has 2 divisors, whose sum is σ = 23120214124254. Its totient is φ = 23120214124252.
The previous prime is 23120214124229. The next prime is 23120214124283. The reversal of 23120214124253 is 35242141202132.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 22183892760484 + 936321363769 = 4709978^2 + 967637^2 .
It is a cyclic number.
It is not a de Polignac number, because 23120214124253 - 28 = 23120214123997 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23120214124213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11560107062126 + 11560107062127.
It is an arithmetic number, because the mean of its divisors is an integer number (11560107062127).
Almost surely, 223120214124253 is an apocalyptic number.
It is an amenable number.
23120214124253 is a deficient number, since it is larger than the sum of its proper divisors (1).
23120214124253 is an equidigital number, since it uses as much as digits as its factorization.
23120214124253 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 23040, while the sum is 32.
Adding to 23120214124253 its reverse (35242141202132), we get a palindrome (58362355326385).
The spelling of 23120214124253 in words is "twenty-three trillion, one hundred twenty billion, two hundred fourteen million, one hundred twenty-four thousand, two hundred fifty-three".
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