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231222023112013 is a prime number
BaseRepresentation
bin110100100100101110010010…
…100011010100010101001101
31010022200121110100101221020021
4310210232102203110111031
5220301320200404041023
62135433533033022141
766463145166045523
oct6444562243242515
91108617410357207
10231222023112013
116774678911250a
1221b24463854951
139c031b286a84b
1441152c4374313
151bae9371ea35d
hexd24b928d454d

231222023112013 has 2 divisors, whose sum is σ = 231222023112014. Its totient is φ = 231222023112012.

The previous prime is 231222023111971. The next prime is 231222023112037. The reversal of 231222023112013 is 310211320222132.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 163856307605769 + 67365715506244 = 12800637^2 + 8207662^2 .

It is a cyclic number.

It is not a de Polignac number, because 231222023112013 - 217 = 231222022980941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (231222023113013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115611011556006 + 115611011556007.

It is an arithmetic number, because the mean of its divisors is an integer number (115611011556007).

Almost surely, 2231222023112013 is an apocalyptic number.

It is an amenable number.

231222023112013 is a deficient number, since it is larger than the sum of its proper divisors (1).

231222023112013 is an equidigital number, since it uses as much as digits as its factorization.

231222023112013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 231222023112013 its reverse (310211320222132), we get a palindrome (541433343334145).

The spelling of 231222023112013 in words is "two hundred thirty-one trillion, two hundred twenty-two billion, twenty-three million, one hundred twelve thousand, thirteen".