Base | Representation |
---|---|
bin | 1101011101101101011… |
… | …0100111000001111111 |
3 | 211010001121222102111021 |
4 | 3113123112213001333 |
5 | 12242212212412111 |
6 | 254133001005011 |
7 | 22466106331063 |
oct | 3273326470177 |
9 | 733047872437 |
10 | 231313404031 |
11 | 8a110428106 |
12 | 389b6483767 |
13 | 18a74833308 |
14 | b2a4b39aa3 |
15 | 603c539d71 |
hex | 35db5a707f |
231313404031 has 2 divisors, whose sum is σ = 231313404032. Its totient is φ = 231313404030.
The previous prime is 231313404019. The next prime is 231313404061. The reversal of 231313404031 is 130404313132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 231313404031 - 25 = 231313403999 is a prime.
It is a super-2 number, since 2×2313134040312 (a number of 24 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 231313403987 and 231313404005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231313404001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115656702015 + 115656702016.
It is an arithmetic number, because the mean of its divisors is an integer number (115656702016).
Almost surely, 2231313404031 is an apocalyptic number.
231313404031 is a deficient number, since it is larger than the sum of its proper divisors (1).
231313404031 is an equidigital number, since it uses as much as digits as its factorization.
231313404031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 231313404031 its reverse (130404313132), we get a palindrome (361717717163).
The spelling of 231313404031 in words is "two hundred thirty-one billion, three hundred thirteen million, four hundred four thousand, thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •