Base | Representation |
---|---|
bin | 1010100001001111000101… |
… | …01000110010001111001111 |
3 | 10000220102020212200011102021 |
4 | 11100213202220302033033 |
5 | 11012444222003400221 |
6 | 121110441520511011 |
7 | 4605150340141234 |
oct | 520474250621717 |
9 | 100812225604367 |
10 | 23132201231311 |
11 | 74093475a3577 |
12 | 271721347b467 |
13 | cba484a5b3a3 |
14 | 59d866adb78b |
15 | 2a1ac5800041 |
hex | 1509e2a323cf |
23132201231311 has 2 divisors, whose sum is σ = 23132201231312. Its totient is φ = 23132201231310.
The previous prime is 23132201231291. The next prime is 23132201231393. The reversal of 23132201231311 is 11313210223132.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 23132201231311 - 225 = 23132167676879 is a prime.
It is a super-2 number, since 2×231322012313112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23132201231411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11566100615655 + 11566100615656.
It is an arithmetic number, because the mean of its divisors is an integer number (11566100615656).
Almost surely, 223132201231311 is an apocalyptic number.
23132201231311 is a deficient number, since it is larger than the sum of its proper divisors (1).
23132201231311 is an equidigital number, since it uses as much as digits as its factorization.
23132201231311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 23132201231311 its reverse (11313210223132), we get a palindrome (34445411454443).
The spelling of 23132201231311 in words is "twenty-three trillion, one hundred thirty-two billion, two hundred one million, two hundred thirty-one thousand, three hundred eleven".
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