Base | Representation |
---|---|
bin | 110100100110011101011011… |
… | …010010010111101011101111 |
3 | 1010100010000110210102021112121 |
4 | 310212131123102113223233 |
5 | 220310244043340203303 |
6 | 2140004430141413411 |
7 | 66504601303316164 |
oct | 6446353322275357 |
9 | 1110100423367477 |
10 | 231341355006703 |
11 | 67792354932187 |
12 | 21b4360786a267 |
13 | 9c1151c502016 |
14 | 411ada4a8606b |
15 | 1bb2abd6cd9bd |
hex | d2675b497aef |
231341355006703 has 2 divisors, whose sum is σ = 231341355006704. Its totient is φ = 231341355006702.
The previous prime is 231341355006661. The next prime is 231341355006709. The reversal of 231341355006703 is 307600553143132.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231341355006703 - 225 = 231341321452271 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 231341355006703.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231341355006709) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115670677503351 + 115670677503352.
It is an arithmetic number, because the mean of its divisors is an integer number (115670677503352).
Almost surely, 2231341355006703 is an apocalyptic number.
231341355006703 is a deficient number, since it is larger than the sum of its proper divisors (1).
231341355006703 is an equidigital number, since it uses as much as digits as its factorization.
231341355006703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 680400, while the sum is 43.
The spelling of 231341355006703 in words is "two hundred thirty-one trillion, three hundred forty-one billion, three hundred fifty-five million, six thousand, seven hundred three".
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