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2313434113 is a prime number
BaseRepresentation
bin1000100111100100…
…0011010000000001
312222020010121222221
42021321003100001
514214214342423
61021320531041
7111220602604
oct21171032001
95866117887
102313434113
11a87967321
12546920a81
132ab399b33
1417d36833b
15d8176e5d
hex89e43401

2313434113 has 2 divisors, whose sum is σ = 2313434114. Its totient is φ = 2313434112.

The previous prime is 2313434111. The next prime is 2313434161. The reversal of 2313434113 is 3114343132.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1397040129 + 916393984 = 37377^2 + 30272^2 .

It is a cyclic number.

It is not a de Polignac number, because 2313434113 - 21 = 2313434111 is a prime.

Together with 2313434111, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (2313434111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1156717056 + 1156717057.

It is an arithmetic number, because the mean of its divisors is an integer number (1156717057).

Almost surely, 22313434113 is an apocalyptic number.

It is an amenable number.

2313434113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2313434113 is an equidigital number, since it uses as much as digits as its factorization.

2313434113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2592, while the sum is 25.

The square root of 2313434113 is about 48098.1716180563. The cubic root of 2313434113 is about 1322.5711503632.

Adding to 2313434113 its reverse (3114343132), we get a palindrome (5427777245).

The spelling of 2313434113 in words is "two billion, three hundred thirteen million, four hundred thirty-four thousand, one hundred thirteen".