Base | Representation |
---|---|
bin | 10101100011010001… |
… | …010110111011110011 |
3 | 2012201200121121212121 |
4 | 111203101112323303 |
5 | 334342411100001 |
6 | 14344105335111 |
7 | 1446303366412 |
oct | 254321267363 |
9 | 65650547777 |
10 | 23140331251 |
11 | 98a5128404 |
12 | 4599797497 |
13 | 224a1841cb |
14 | 11973bb479 |
15 | 9067ce6a1 |
hex | 563456ef3 |
23140331251 has 2 divisors, whose sum is σ = 23140331252. Its totient is φ = 23140331250.
The previous prime is 23140331239. The next prime is 23140331317. The reversal of 23140331251 is 15213304132.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23140331251 is a prime.
It is not a weakly prime, because it can be changed into another prime (23140332251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11570165625 + 11570165626.
It is an arithmetic number, because the mean of its divisors is an integer number (11570165626).
Almost surely, 223140331251 is an apocalyptic number.
23140331251 is a deficient number, since it is larger than the sum of its proper divisors (1).
23140331251 is an equidigital number, since it uses as much as digits as its factorization.
23140331251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 23140331251 its reverse (15213304132), we get a palindrome (38353635383).
The spelling of 23140331251 in words is "twenty-three billion, one hundred forty million, three hundred thirty-one thousand, two hundred fifty-one".
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