Base | Representation |
---|---|
bin | 100001101011011000001… |
… | …111000100011010010101 |
3 | 22012020122221211010221011 |
4 | 201223120033010122111 |
5 | 300404211434443013 |
6 | 4531103430252221 |
7 | 326130004261225 |
oct | 41533017043225 |
9 | 8166587733834 |
10 | 2314320234133 |
11 | 81255248aa26 |
12 | 3146451b7071 |
13 | 13a3161357ab |
14 | 80029828085 |
15 | 40302978c3d |
hex | 21ad83c4695 |
2314320234133 has 2 divisors, whose sum is σ = 2314320234134. Its totient is φ = 2314320234132.
The previous prime is 2314320234077. The next prime is 2314320234151. The reversal of 2314320234133 is 3314320234132.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2209601979729 + 104718254404 = 1486473^2 + 323602^2 .
It is a cyclic number.
It is not a de Polignac number, because 2314320234133 - 217 = 2314320103061 is a prime.
It is a super-2 number, since 2×23143202341332 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2314320234095 and 2314320234104.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2314320231133) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157160117066 + 1157160117067.
It is an arithmetic number, because the mean of its divisors is an integer number (1157160117067).
Almost surely, 22314320234133 is an apocalyptic number.
It is an amenable number.
2314320234133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314320234133 is an equidigital number, since it uses as much as digits as its factorization.
2314320234133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 31.
Adding to 2314320234133 its reverse (3314320234132), we get a palindrome (5628640468265).
Subtracting 2314320234133 from its reverse (3314320234132), we obtain a palindrome (999999999999).
The spelling of 2314320234133 in words is "two trillion, three hundred fourteen billion, three hundred twenty million, two hundred thirty-four thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •