Base | Representation |
---|---|
bin | 1101011110001011111… |
… | …0100010101100100111 |
3 | 211010101112122211222212 |
4 | 3113202332202230213 |
5 | 12242442434000201 |
6 | 254153410314035 |
7 | 22502221461161 |
oct | 3274276425447 |
9 | 733345584885 |
10 | 231441312551 |
11 | 8a176650729 |
12 | 38a3128891b |
13 | 18a95198b27 |
14 | b2b7b13931 |
15 | 60488a3abb |
hex | 35e2fa2b27 |
231441312551 has 2 divisors, whose sum is σ = 231441312552. Its totient is φ = 231441312550.
The previous prime is 231441312481. The next prime is 231441312581. The reversal of 231441312551 is 155213144132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 231441312551 - 210 = 231441311527 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (231441312581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 115720656275 + 115720656276.
It is an arithmetic number, because the mean of its divisors is an integer number (115720656276).
Almost surely, 2231441312551 is an apocalyptic number.
231441312551 is a deficient number, since it is larger than the sum of its proper divisors (1).
231441312551 is an equidigital number, since it uses as much as digits as its factorization.
231441312551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14400, while the sum is 32.
Adding to 231441312551 its reverse (155213144132), we get a palindrome (386654456683).
The spelling of 231441312551 in words is "two hundred thirty-one billion, four hundred forty-one million, three hundred twelve thousand, five hundred fifty-one".
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