Base | Representation |
---|---|
bin | 100001101011011111000… |
… | …010001111111001010011 |
3 | 22012020221220110222211102 |
4 | 201223133002033321103 |
5 | 300404430141020221 |
6 | 4531123023335015 |
7 | 326132561034104 |
oct | 41533702177123 |
9 | 8166856428742 |
10 | 2314434313811 |
11 | 812600918754 |
12 | 31467745146b |
13 | 13a333968a69 |
14 | 8003aa423ab |
15 | 4030c9b030b |
hex | 21adf08fe53 |
2314434313811 has 2 divisors, whose sum is σ = 2314434313812. Its totient is φ = 2314434313810.
The previous prime is 2314434313777. The next prime is 2314434313813. The reversal of 2314434313811 is 1183134344132.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2314434313811 is a prime.
Together with 2314434313813, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (2314434313813) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1157217156905 + 1157217156906.
It is an arithmetic number, because the mean of its divisors is an integer number (1157217156906).
Almost surely, 22314434313811 is an apocalyptic number.
2314434313811 is a deficient number, since it is larger than the sum of its proper divisors (1).
2314434313811 is an equidigital number, since it uses as much as digits as its factorization.
2314434313811 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 82944, while the sum is 38.
Adding to 2314434313811 its reverse (1183134344132), we get a palindrome (3497568657943).
The spelling of 2314434313811 in words is "two trillion, three hundred fourteen billion, four hundred thirty-four million, three hundred thirteen thousand, eight hundred eleven".
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