Base | Representation |
---|---|
bin | 110100101001010000011000… |
… | …001101010101001000110000 |
3 | 1010100210101102221000211100221 |
4 | 310221100120031111020300 |
5 | 220321421103300443100 |
6 | 2140233004543022424 |
7 | 66524513022440536 |
oct | 6451203015251060 |
9 | 1110711387024327 |
10 | 231533503140400 |
11 | 67856897502a7a |
12 | 21b748b189aa14 |
13 | 9c26691ba5656 |
14 | 41263d2020156 |
15 | 1bb7ab766901a |
hex | d29418355230 |
231533503140400 has 60 divisors (see below), whose sum is σ = 562961159945352. Its totient is φ = 91497577131520.
The previous prime is 231533503140361. The next prime is 231533503140437. The reversal of 231533503140400 is 4041305335132.
It is a super-2 number, since 2×2315335031404002 (a number of 30 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3486917149 + ... + 3486983548.
Almost surely, 2231533503140400 is an apocalyptic number.
231533503140400 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
231533503140400 is an abundant number, since it is smaller than the sum of its proper divisors (331427656804952).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
231533503140400 is a wasteful number, since it uses less digits than its factorization.
231533503140400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6973900798 (or 6973900787 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 34.
Adding to 231533503140400 its reverse (4041305335132), we get a palindrome (235574808475532).
The spelling of 231533503140400 in words is "two hundred thirty-one trillion, five hundred thirty-three billion, five hundred three million, one hundred forty thousand, four hundred".
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