Base | Representation |
---|---|
bin | 1010100001111001101001… |
… | …01101111000001011100111 |
3 | 10000222121020110120010110112 |
4 | 11100330310231320023213 |
5 | 11013333022100301232 |
6 | 121125141244243235 |
7 | 4606616542126004 |
oct | 520746455701347 |
9 | 100877213503415 |
10 | 23155053134567 |
11 | 7418003930732 |
12 | 271b73054051b |
13 | cbc687236a33 |
14 | 5a09d3a788ab |
15 | 2a24b1b094b2 |
hex | 150f34b782e7 |
23155053134567 has 2 divisors, whose sum is σ = 23155053134568. Its totient is φ = 23155053134566.
The previous prime is 23155053134561. The next prime is 23155053134569. The reversal of 23155053134567 is 76543135055132.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 23155053134567 - 222 = 23155048940263 is a prime.
Together with 23155053134569, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23155053134561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11577526567283 + 11577526567284.
It is an arithmetic number, because the mean of its divisors is an integer number (11577526567284).
Almost surely, 223155053134567 is an apocalyptic number.
23155053134567 is a deficient number, since it is larger than the sum of its proper divisors (1).
23155053134567 is an equidigital number, since it uses as much as digits as its factorization.
23155053134567 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5670000, while the sum is 50.
Adding to 23155053134567 its reverse (76543135055132), we get a palindrome (99698188189699).
The spelling of 23155053134567 in words is "twenty-three trillion, one hundred fifty-five billion, fifty-three million, one hundred thirty-four thousand, five hundred sixty-seven".
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