Base | Representation |
---|---|
bin | 1010100010101110110000… |
… | …10111011100010011111111 |
3 | 10001002022211202021211010111 |
4 | 11101113120113130103333 |
5 | 11014314422020123242 |
6 | 121150215004050451 |
7 | 4611646303660546 |
oct | 521273027342377 |
9 | 101068752254114 |
10 | 23183568520447 |
11 | 7429107043145 |
12 | 272516a233a27 |
13 | cc227cb65a2a |
14 | 5a213ac6715d |
15 | 2a30d0227817 |
hex | 1515d85dc4ff |
23183568520447 has 2 divisors, whose sum is σ = 23183568520448. Its totient is φ = 23183568520446.
The previous prime is 23183568520433. The next prime is 23183568520487. The reversal of 23183568520447 is 74402586538132.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-23183568520447 is a prime.
It is a super-2 number, since 2×231835685204472 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 23183568520391 and 23183568520400.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23183568520487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11591784260223 + 11591784260224.
It is an arithmetic number, because the mean of its divisors is an integer number (11591784260224).
Almost surely, 223183568520447 is an apocalyptic number.
23183568520447 is a deficient number, since it is larger than the sum of its proper divisors (1).
23183568520447 is an equidigital number, since it uses as much as digits as its factorization.
23183568520447 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 38707200, while the sum is 58.
The spelling of 23183568520447 in words is "twenty-three trillion, one hundred eighty-three billion, five hundred sixty-eight million, five hundred twenty thousand, four hundred forty-seven".
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