Base | Representation |
---|---|
bin | 1101100000010010011… |
… | …0011010100101010111 |
3 | 211011211212010010121202 |
4 | 3120010212122211113 |
5 | 12300121341210312 |
6 | 254325401103115 |
7 | 22522211321411 |
oct | 3300446324527 |
9 | 734755103552 |
10 | 232005413207 |
11 | 8a436009917 |
12 | 38b6a187a9b |
13 | 18b550054b9 |
14 | b32c9d39b1 |
15 | 607d17e9c2 |
hex | 360499a957 |
232005413207 has 2 divisors, whose sum is σ = 232005413208. Its totient is φ = 232005413206.
The previous prime is 232005413147. The next prime is 232005413209. The reversal of 232005413207 is 702314500232.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 232005413207 - 228 = 231736977751 is a prime.
Together with 232005413209, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 232005413207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232005413209) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116002706603 + 116002706604.
It is an arithmetic number, because the mean of its divisors is an integer number (116002706604).
Almost surely, 2232005413207 is an apocalyptic number.
232005413207 is a deficient number, since it is larger than the sum of its proper divisors (1).
232005413207 is an equidigital number, since it uses as much as digits as its factorization.
232005413207 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10080, while the sum is 29.
Adding to 232005413207 its reverse (702314500232), we get a palindrome (934319913439).
The spelling of 232005413207 in words is "two hundred thirty-two billion, five million, four hundred thirteen thousand, two hundred seven".
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