Base | Representation |
---|---|
bin | 100001110000110001011… |
… | …001100101100111111101 |
3 | 22012210121112102012012211 |
4 | 201300301121211213331 |
5 | 301003041422144013 |
6 | 4533502213300421 |
7 | 326423342136655 |
oct | 41606131454775 |
9 | 8183545365184 |
10 | 2320111131133 |
11 | 814a54280614 |
12 | 3157a0634711 |
13 | 13aa29aaaa73 |
14 | 80418965365 |
15 | 4054105a23d |
hex | 21c316659fd |
2320111131133 has 2 divisors, whose sum is σ = 2320111131134. Its totient is φ = 2320111131132.
The previous prime is 2320111131119. The next prime is 2320111131157. The reversal of 2320111131133 is 3311311110232.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1393431510969 + 926679620164 = 1180437^2 + 962642^2 .
It is a cyclic number.
It is not a de Polignac number, because 2320111131133 - 25 = 2320111131101 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2320111131433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160055565566 + 1160055565567.
It is an arithmetic number, because the mean of its divisors is an integer number (1160055565567).
Almost surely, 22320111131133 is an apocalyptic number.
It is an amenable number.
2320111131133 is a deficient number, since it is larger than the sum of its proper divisors (1).
2320111131133 is an equidigital number, since it uses as much as digits as its factorization.
2320111131133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 2320111131133 its reverse (3311311110232), we get a palindrome (5631422241365).
The spelling of 2320111131133 in words is "two trillion, three hundred twenty billion, one hundred eleven million, one hundred thirty-one thousand, one hundred thirty-three".
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