2320111131433 has 2 divisors, whose sum is σ = 2320111131434. Its totient is φ = 2320111131432.

The previous prime is 2320111131347. The next prime is 2320111131449. The reversal of 2320111131433 is 3341311110232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2081579501824 + 238531629609 = 1442768^2 + 488397^2 .

It is a cyclic number.

It is not a de Polignac number, because 2320111131433 - 2³³ = 2311521196841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2320111131398 and 2320111131407.

It is not a weakly prime, because it can be changed into another prime (2320111131133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160055565716 + 1160055565717.

It is an arithmetic number, because the mean of its divisors is an integer number (1160055565717).

Almost surely, 2^{2320111131433} is an apocalyptic number.

It is an amenable number.

2320111131433 is a deficient number, since it is larger than the sum of its proper divisors (1).

2320111131433 is an equidigital number, since it uses as much as digits as its factorization.

2320111131433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 2320111131433 its reverse (3341311110232), we get a palindrome (5661422241665).

The spelling of 2320111131433 in words is "two trillion, three hundred twenty billion, one hundred eleven million, one hundred thirty-one thousand, four hundred thirty-three".