Base | Representation |
---|---|
bin | 110100110000011110111110… |
… | …011011111010111011101111 |
3 | 1010102112212112111200101011112 |
4 | 310300132332123322323233 |
5 | 220403040334041102002 |
6 | 2141253113003542235 |
7 | 66605425662454565 |
oct | 6460367633727357 |
9 | 1112485474611145 |
10 | 232030213222127 |
11 | 67a28508392151 |
12 | 22035014b2a97b |
13 | 9c61480560c08 |
14 | 414247232da35 |
15 | 1bc598953b852 |
hex | d307be6faeef |
232030213222127 has 2 divisors, whose sum is σ = 232030213222128. Its totient is φ = 232030213222126.
The previous prime is 232030213222123. The next prime is 232030213222259. The reversal of 232030213222127 is 721222312030232.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 232030213222127 - 22 = 232030213222123 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 232030213222093 and 232030213222102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (232030213222123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 116015106611063 + 116015106611064.
It is an arithmetic number, because the mean of its divisors is an integer number (116015106611064).
Almost surely, 2232030213222127 is an apocalyptic number.
232030213222127 is a deficient number, since it is larger than the sum of its proper divisors (1).
232030213222127 is an equidigital number, since it uses as much as digits as its factorization.
232030213222127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 32.
Adding to 232030213222127 its reverse (721222312030232), we get a palindrome (953252525252359).
The spelling of 232030213222127 in words is "two hundred thirty-two trillion, thirty billion, two hundred thirteen million, two hundred twenty-two thousand, one hundred twenty-seven".
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