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23211233249 is a prime number
BaseRepresentation
bin10101100111011111…
…110100111111100001
32012220122000211010112
4111213133310333201
5340014033430444
614355121141105
71451124140651
oct254737647741
965818024115
1023211233249
1199311550a6
1245b948a795
13225ba7a459
1411a2996361
1590cb3769e
hex5677f4fe1

23211233249 has 2 divisors, whose sum is σ = 23211233250. Its totient is φ = 23211233248.

The previous prime is 23211233183. The next prime is 23211233251. The reversal of 23211233249 is 94233211232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22480504225 + 730729024 = 149935^2 + 27032^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-23211233249 is a prime.

It is a super-4 number, since 4×232112332494 (a number of 43 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 23211233251, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (23211233299) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11605616624 + 11605616625.

It is an arithmetic number, because the mean of its divisors is an integer number (11605616625).

Almost surely, 223211233249 is an apocalyptic number.

It is an amenable number.

23211233249 is a deficient number, since it is larger than the sum of its proper divisors (1).

23211233249 is an equidigital number, since it uses as much as digits as its factorization.

23211233249 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15552, while the sum is 32.

The spelling of 23211233249 in words is "twenty-three billion, two hundred eleven million, two hundred thirty-three thousand, two hundred forty-nine".