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23212113101 is a prime number
BaseRepresentation
bin10101100111100011…
…001011110011001101
32012220200200112001122
4111213203023303031
5340014300104401
614355152050325
71451134464062
oct254743136315
965820615048
1023212113101
1199316a6151
1245b98339a5
13225bcc7a88
1411a2b44c69
1590cc5d21b
hex5678cbccd

23212113101 has 2 divisors, whose sum is σ = 23212113102. Its totient is φ = 23212113100.

The previous prime is 23212113091. The next prime is 23212113103. The reversal of 23212113101 is 10131121232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22649949001 + 562164100 = 150499^2 + 23710^2 .

It is a cyclic number.

It is not a de Polignac number, because 23212113101 - 26 = 23212113037 is a prime.

It is a super-2 number, since 2×232121131012 (a number of 22 digits) contains 22 as substring.

Together with 23212113103, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 23212113101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23212113103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606056550 + 11606056551.

It is an arithmetic number, because the mean of its divisors is an integer number (11606056551).

Almost surely, 223212113101 is an apocalyptic number.

It is an amenable number.

23212113101 is a deficient number, since it is larger than the sum of its proper divisors (1).

23212113101 is an equidigital number, since it uses as much as digits as its factorization.

23212113101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 23212113101 its reverse (10131121232), we get a palindrome (33343234333).

The spelling of 23212113101 in words is "twenty-three billion, two hundred twelve million, one hundred thirteen thousand, one hundred one".