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23213132021 is a prime number
BaseRepresentation
bin10101100111100111…
…000100100011110101
32012220202121021202102
4111213213010203311
5340020030211041
614355225551445
71451146236512
oct254747044365
965822537672
1023213132021
119932231732
1245ba045585
13225c2937a1
1411a2d2c309
1590cdb009b
hex5679c48f5

23213132021 has 2 divisors, whose sum is σ = 23213132022. Its totient is φ = 23213132020.

The previous prime is 23213132017. The next prime is 23213132023. The reversal of 23213132021 is 12023131232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17986564996 + 5226567025 = 134114^2 + 72295^2 .

It is a cyclic number.

It is not a de Polignac number, because 23213132021 - 22 = 23213132017 is a prime.

Together with 23213132023, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23213131984 and 23213132002.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23213132023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11606566010 + 11606566011.

It is an arithmetic number, because the mean of its divisors is an integer number (11606566011).

Almost surely, 223213132021 is an apocalyptic number.

It is an amenable number.

23213132021 is a deficient number, since it is larger than the sum of its proper divisors (1).

23213132021 is an equidigital number, since it uses as much as digits as its factorization.

23213132021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 23213132021 its reverse (12023131232), we get a palindrome (35236263253).

The spelling of 23213132021 in words is "twenty-three billion, two hundred thirteen million, one hundred thirty-two thousand, twenty-one".