Base | Representation |
---|---|
bin | 100001110010000110101… |
… | …101001110101010001111 |
3 | 22012221022021111022020021 |
4 | 201302012231032222033 |
5 | 301014004314441221 |
6 | 4534300221203011 |
7 | 326503661220142 |
oct | 41620655165217 |
9 | 8187267438207 |
10 | 2321542343311 |
11 | 8156191484a4 |
12 | 315b1ba00467 |
13 | 13abc7467189 |
14 | 80512a80059 |
15 | 405c6a18041 |
hex | 21c86b4ea8f |
2321542343311 has 2 divisors, whose sum is σ = 2321542343312. Its totient is φ = 2321542343310.
The previous prime is 2321542343249. The next prime is 2321542343353. The reversal of 2321542343311 is 1133432451232.
2321542343311 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2321542343311 - 211 = 2321542341263 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2321542343371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1160771171655 + 1160771171656.
It is an arithmetic number, because the mean of its divisors is an integer number (1160771171656).
Almost surely, 22321542343311 is an apocalyptic number.
2321542343311 is a deficient number, since it is larger than the sum of its proper divisors (1).
2321542343311 is an equidigital number, since it uses as much as digits as its factorization.
2321542343311 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 51840, while the sum is 34.
Adding to 2321542343311 its reverse (1133432451232), we get a palindrome (3454974794543).
The spelling of 2321542343311 in words is "two trillion, three hundred twenty-one billion, five hundred forty-two million, three hundred forty-three thousand, three hundred eleven".
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