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23223400413047 is a prime number
BaseRepresentation
bin1010100011111000111101…
…00010000011011101110111
310001020010122201000121121222
411101330132202003131313
511020443011001204142
6121220403255500555
74614556340324402
oct521743642033567
9101203581017558
1023223400413047
117443a9711164a
122730a2598775b
13cc5c5a149553
145a4038d94d39
152a41620a4bd2
hex151f1e883777

23223400413047 has 2 divisors, whose sum is σ = 23223400413048. Its totient is φ = 23223400413046.

The previous prime is 23223400412987. The next prime is 23223400413049. The reversal of 23223400413047 is 74031400432232.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 23223400413047 - 26 = 23223400412983 is a prime.

Together with 23223400413049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 23223400412998 and 23223400413016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23223400413049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11611700206523 + 11611700206524.

It is an arithmetic number, because the mean of its divisors is an integer number (11611700206524).

Almost surely, 223223400413047 is an apocalyptic number.

23223400413047 is a deficient number, since it is larger than the sum of its proper divisors (1).

23223400413047 is an equidigital number, since it uses as much as digits as its factorization.

23223400413047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 35.

Adding to 23223400413047 its reverse (74031400432232), we get a palindrome (97254800845279).

The spelling of 23223400413047 in words is "twenty-three trillion, two hundred twenty-three billion, four hundred million, four hundred thirteen thousand, forty-seven".