Search a number
-
+
2323213203149 is a prime number
BaseRepresentation
bin100001110011101010010…
…011000011011011001101
322020002121201111210000222
4201303222103003123031
5301030420040000044
64535134105401125
7326563250254466
oct41635223033315
98202551453028
102323213203149
118162a63181a3
123163074991a5
1313b10267cc37
148063093bd6d
15406735628ee
hex21cea4c36cd

2323213203149 has 2 divisors, whose sum is σ = 2323213203150. Its totient is φ = 2323213203148.

The previous prime is 2323213203067. The next prime is 2323213203151. The reversal of 2323213203149 is 9413023123232.

2323213203149 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2215057726249 + 108155476900 = 1488307^2 + 328870^2 .

It is a cyclic number.

It is not a de Polignac number, because 2323213203149 - 240 = 1223701575373 is a prime.

Together with 2323213203151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2323213205149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1161606601574 + 1161606601575.

It is an arithmetic number, because the mean of its divisors is an integer number (1161606601575).

Almost surely, 22323213203149 is an apocalyptic number.

It is an amenable number.

2323213203149 is a deficient number, since it is larger than the sum of its proper divisors (1).

2323213203149 is an equidigital number, since it uses as much as digits as its factorization.

2323213203149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 35.

The spelling of 2323213203149 in words is "two trillion, three hundred twenty-three billion, two hundred thirteen million, two hundred three thousand, one hundred forty-nine".