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232334341340 = 22511616717067
BaseRepresentation
bin1101100001100000110…
…1001011010011011100
3211012200210001102012012
43120120031023103130
512301310042410330
6254422151130352
722533314213513
oct3303015132334
9735623042165
10232334341340
118a594751452
12390403739b8
1318ba81c142a
14b36057767a
15609bea4c95
hex361834b4dc

232334341340 has 12 divisors (see below), whose sum is σ = 487902116856. Its totient is φ = 92933736528.

The previous prime is 232334341243. The next prime is 232334341409. The reversal of 232334341340 is 43143433232.

It is a junction number, because it is equal to n+sod(n) for n = 232334341297 and 232334341306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5808358514 + ... + 5808358553.

It is an arithmetic number, because the mean of its divisors is an integer number (40658509738).

Almost surely, 2232334341340 is an apocalyptic number.

232334341340 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

232334341340 is an abundant number, since it is smaller than the sum of its proper divisors (255567775516).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

232334341340 is a wasteful number, since it uses less digits than its factorization.

232334341340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11616717076 (or 11616717074 counting only the distinct ones).

The product of its (nonzero) digits is 62208, while the sum is 32.

Adding to 232334341340 its reverse (43143433232), we get a palindrome (275477774572).

The spelling of 232334341340 in words is "two hundred thirty-two billion, three hundred thirty-four million, three hundred forty-one thousand, three hundred forty".

Divisors: 1 2 4 5 10 20 11616717067 23233434134 46466868268 58083585335 116167170670 232334341340