Search a number
-
+
23234331220333 is a prime number
BaseRepresentation
bin1010100100001101010100…
…00011110001100101101101
310001021011212111021011022021
411102012222003301211231
511021132402243022313
6121225412052550141
74615424246545252
oct522065203614555
9101234774234267
1023234331220333
11744869628a982
122732b76622351
13cc6cac92895c
145a47949b3429
152a45a1a2778d
hex1521aa0f196d

23234331220333 has 2 divisors, whose sum is σ = 23234331220334. Its totient is φ = 23234331220332.

The previous prime is 23234331220253. The next prime is 23234331220337. The reversal of 23234331220333 is 33302213343232.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 17875282158889 + 5359049061444 = 4227917^2 + 2314962^2 .

It is a cyclic number.

It is not a de Polignac number, because 23234331220333 - 217 = 23234331089261 is a prime.

It is a super-2 number, since 2×232343312203332 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (23234331220337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11617165610166 + 11617165610167.

It is an arithmetic number, because the mean of its divisors is an integer number (11617165610167).

Almost surely, 223234331220333 is an apocalyptic number.

It is an amenable number.

23234331220333 is a deficient number, since it is larger than the sum of its proper divisors (1).

23234331220333 is an equidigital number, since it uses as much as digits as its factorization.

23234331220333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 139968, while the sum is 34.

Adding to 23234331220333 its reverse (33302213343232), we get a palindrome (56536544563565).

The spelling of 23234331220333 in words is "twenty-three trillion, two hundred thirty-four billion, three hundred thirty-one million, two hundred twenty thousand, three hundred thirty-three".