Base | Representation |
---|---|
bin | 1010100110001001100000… |
… | …00100101011001000011101 |
3 | 10001111112222001002000010121 |
4 | 11103010300010223020131 |
5 | 11023230424023044123 |
6 | 121320200012234541 |
7 | 4623304414020646 |
oct | 523046004531035 |
9 | 101445861060117 |
10 | 23301004112413 |
11 | 747399a402585 |
12 | 2743a8316ba51 |
13 | 100037698c4a1 |
14 | 5a7abb7946cd |
15 | 2a61a4ecd75d |
hex | 15313012b21d |
23301004112413 has 2 divisors, whose sum is σ = 23301004112414. Its totient is φ = 23301004112412.
The previous prime is 23301004112387. The next prime is 23301004112437. The reversal of 23301004112413 is 31421140010332.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13330837904164 + 9970166208249 = 3651142^2 + 3157557^2 .
It is a cyclic number.
It is not a de Polignac number, because 23301004112413 - 213 = 23301004104221 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (23301004112453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 11650502056206 + 11650502056207.
It is an arithmetic number, because the mean of its divisors is an integer number (11650502056207).
Almost surely, 223301004112413 is an apocalyptic number.
It is an amenable number.
23301004112413 is a deficient number, since it is larger than the sum of its proper divisors (1).
23301004112413 is an equidigital number, since it uses as much as digits as its factorization.
23301004112413 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 23301004112413 its reverse (31421140010332), we get a palindrome (54722144122745).
The spelling of 23301004112413 in words is "twenty-three trillion, three hundred one billion, four million, one hundred twelve thousand, four hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •